Thanks everybody. Its a very nice study. Few of you got it right. Anyways here is full solution. Hope you have the reddit PGN addon installed:
[pgn][Event "Mannheim"] [Site "?"] [Date "1914.??.??"] [Round "?"] [White "Mieses, J."] [Black "Post, E."] [Result "0-1"] [SetUp "1"] [FEN "8/1p6/8/2p4R/1kP5/3K4/p7/3B4 w - - 0 1"] [PlyCount "7"] [EventDate "1914.??.??"] [SourceDate "2005.01.24"]
{It's a position taken from a genuine historic game - one played exactly a
hundred years ago. Four different opinions are quoted, each contradicting the
previous one about who is actually winning. 1.) An amateur, who had
strolled by the board, whispered to a friend: The black pawn on a2 is going to
queen, and White can do absolutely nothing to stop it. So Black is winning!
2) His friend, a stronger player, didn't agree: "Come on, wake up! White plays
1.Rh7! a1Q 2.Rxb7+ Ka3 3.Ra7+ Kb2 4.Rxa1 Kxa1. It's a clear win for White!"
3) At the board White, an expert player, studied the position for a while and
then resigned! He stretched out his hand and said to his opponent: It's quite
hopeless, really. After 1.Rh7 you play 1...Ka5 2.Rxb7 Ka6 3.Rb8 Ka7 and I
can't stop you from getting the queen. So Black obviously wins. 4) His
opponent, who was an even stronger player, accepted his resignation and then,
to the horror of the white player, said: "Actually I was just about to resign
myself. I saw that after 1.Rh7! Ka5 you simply play 2.Rh8! The a-pawn is lost
and the game is over. So actually White was winning." So who was right - or
were all four wrong? I urge you to study the above position and draw your own
independent conclusion. If you can solve the puzzle in your head you should
give yourself a contortionist's pat on the back.} {Solution: the result is
actually a draw!} 1. Rh7 $1 a1=Q $1 (1... Ka5 $2 2. Rxb7 (2. Rh8 $1 $18) 2...
Ka6 3. Rb8 Ka7 $19) 2. Rxb7+ Ka3 3. Ra7+ Kb4 $1 {The key move overlooked by
all.} (3... Kb2 $2 4. Rxa1 Kxa1 $18) 4. Rxa1 {stalemate!} (4. Ra4+ Qxa4 5. Bxa4
Kxa4 6. Ke4 Kb3 (6... Ka5 7. Kd3 Kb4 8. Kd2 Kxc4 9. Kc2 $11) 7. Kd3 Kb4 8. Kd2
Kxc4 9. Kc2 $11 {Carlos Mas.}) 0-1[/pgn]