I’m stumped on a trig identity and need verification. Please help.

16(cosx)2 *(sinx)4 +16(sinx)2 *(cosx)4 =16

16*(cosx)2 *(sinx)2 [(sinx)2 +(cosx)2 ]=16

16*(cosx)2 *(sinx)2 =16

(cosx)2 *(sinx)2 =1

cosx * sinx = ±1

Then it's doesn't because if you need to get 1 there are to cases

(1) 1*1=1

It doesn't work because there is no x gives you cosx=sinx=1

(2) a number multiplied by his reciprocal equals 1

Which means you need to multiply a number smaller than with a number that is greater than one. It doesn't work because -1≤cosx,sinx≤1.

Pss* you can also use sin2x=2cosxsinx like this:

(Cosx)2 *(sinx)2 =1

[(Sin2x)2 ]/4=1

(Sin2x)2 =4

Sin2x=±2

Which doesn't work because -1≤sin2x≤1

*is used it like this:

sin2x=2cosxsinx

(sin2x)/2=cosx*sinx

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