anyone know how to rearrange this equation into this form?

With an maths equation: A. you can add, substract, divide, or multiply boths sides, and the equation still holds. B. When you see: 2y that means 2 multiplied by y, or 2 × y so: 2y - 5x = 2 IS: 2 × y - 5 × x = 2

(1) Add +5x to boths sides to isolate 2y on only one side: 2y - 5x + 5x = 2 + 5x (2) On the LHS -5x +5x cancel each other to give nothing. So: 2y = 2 + 5x (3) Now divide both LHS, and RHS by 2 to isolate y on the LHS: y = 1 + (5 × x ÷ 2) (4) 5 × x ÷ 2 == (5 ÷ 2) × x == 2.5 × x == 2.5 x So we get: y = 1 + 2.5x (5) Finally. Addition is commutative (it commutes or moves). Meaning that the order in which we add does not matter. So: y = 1 + 2.5x == y = 2.5x + 1 (6) We're finished. y = mx + c == y = 2.5x + 1; so m = 2.5, c = 1

So, you can write out your answer out (show your workings) as:

2y - 5x = 2 ; Add 5x to BS

=> 2y = 2 + 5x ; Divide BS by 2 => y = 1 + 2.5x ; Rearrange => y = 2.5x + 1 => m = 2.5, c = 1

Note: BS : 'both sides' => : 'implies that' LHS : Lefthand side RHS : Righthand side == : I'm using this like a triple = sign.

/r/maths Thread Parent Link - i.redd.it